| Chem 109 |
General Chemistry |
Summer 2002 |
| Lecture Notes:: 13 June |
© R. Paselk 2002 |
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Aqueous Solutions, cont.
- How much 1.000 M MgSO4 is needed to make 500.0
mL of a 0.25 M solution.
First convert volumes to Liters: 500.0 mL = 0.5000
L
Can solve as a ratio: (0.5000 L) (0.25 M) = (1.0000
M) (x)
x = (0.25M)(0.5000 L)/(1.0000 M) = 0.125 L
= 0.13 L
Chemical Reactions
Ionic reactions - dissolving and precipitates:
Much of the chemistry around us involves the dissolution of ionic
solids in water to give aqueous solutions and the precipitation
of ions from aqueous solution to give precipitates (solids). So
what I would like to do first is to look a little at the process
of dissolving and the nature of aqueous solutions.
We looked at water in some detail earlier (12
June notes). The thing we need to keep in mind is that the
ions in water are not independent - they dissolve because they
substitute interactions with water molecules for interactions
with counter ions. And they stay in solution because they are
insulated from each other by the water "shells" around
each ion. A couple of corollaries
- First, only so many ions will dissolve until we run out of
water molecules to make the shells, then they will interact with
each other and precipitate out.
- Second, the amount of a given ion which will dissolve in
water depends on the competition between water and its counter
ion for interaction with it. If the ion-ion interaction is very
strong, then they will precipitate out at very low concentrations
etc.
Let's consider some chemical processes:
- Dissolve NaCl in water (overhead) NaCl Æ
Na+(aq) + Cl-(aq)
- Add NaCl solution to a AgNO3 solution. First recall
that each of the ions in solution is in an (aq)ueous complex,
so we can write:
Na+(aq) + Cl-(aq)
+ Ag+(aq) + NO3-(aq)
Æ AgCl(s) + Na+(aq)
+ NO3-(aq)
Notice that two ions don't change, so why show them.
Instead we write a net ionic equation:
Ag+ + Cl- Æ
AgCl(s)
Notice the ions that appeared on both sides are not
shown (in mathematical terms they cancelled)
- Mix barium chloride and potassium sulfate:
Ba2+(aq) + 2 Cl-(aq)
+ 2 K+(aq) + SO42-
Æ BaSO4(s)
+ 2 K+(aq) + 2 Cl-
Again, we want to write a net ionic equation showing
only the ions which reacted:
Ba2+ + SO4-
Æ BaSO4(s)
Notice that net ionic equations are very general expressions.
Essentially they are saying that any time we have these species
present they will react, regardless of what else happens to be
there! (Sometimes folks are confused when they add ions which
should react and they don't. This is usually a case where something
else reacted first, so the ions of interest really weren't there!).
Since all ions in aqueous reactions are considered to be hydrated,
we do not generally include (aq) as part of the formula.
But remember, it is assumed!
Solubility Rules
It is useful to remember some simple "rules" (really
more like guide lines) to help in predicting reactions
- Nitrates (NO3-) are generally soluble.
- Alkali metal (Li+, Na+, K+,
Cs+, and Rb+) and ammonium (NH4+)
salts are nearly all soluble.
- Chloride, bromide, and iodide (Cl-, Br-,
and I-) salts are generally soluble, except for the
salts of silver, lead(II) and mercury(I) (Ag+, Pb2+
and Hg22+).
- Sulfates (other than barium sulfate {BaSO4}, lead(II)
sulfate {PbSO4}, mercury(II) sulfate {HgSO4},
and calcium sulfate {CaSO4}) are soluble.
- Most hydroxides are only slightly soluble (but see rule 2).
- Sulfides (S2-), carbonates (CO32-),
phosphates (PO43-), and chromates (CrO42-)
are only slightly soluble (but see rule 2).
Oxidation/Reduction (Redox) Reactions
In these reactions we see a transfer of electrons from one
atom or molecule to another. First let's look at some terms.
- Oxidation refers to taking electrons away from a substance.
So to oxidize means to behave like oxygen normally does and "steal"
electrons.
- Reduction refers to recieving electrons - it is the opposite
of oxidation.
- Note that oxidation and reduction always go together. When
oxygen oxidizes it is itself reduced (it gains electrons).
© R A Paselk
Last modified 13 June 2002