| Chem 109 |
General Chemistry |
Summer 2002 |
| Lecture Notes::15 July |
© R. Paselk 2002 |
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Solutions
Solution Concentrations-a Review & Some New Stuff.
Solutions: a solution occurs when one chemical is completely
dissolved or dispersed in another. We most commonly think of solutions
as being liquid, but solid solutions also occur, such as the various
metal alloys like steel, brass and bronze.
In a solution the substance present in highest concentration
is considered to be the solvent, while components in lesser amounts
are considered to be solutes. If you dissolve a sugar cube in
water you get a sugar solution, where water is the solvent, and
sugar is the solute.
Example:
- What is the solvent in 80 proof rum: 80 proof = 40% alcohol
in water, so water is the solvent.
- What is the solvent in 151 proof rum: 151 proof = 75.5% alcohol
in water, so alcohol is the solvent.
Concentration Measures
(Check out the problems in the Labbook Appendix!)
Concentration Terms:
- Percent Concentration
- Mass percent
- Volume percent
- Molarity: The most commonly used concentration term
in chemistry = moles of solute dissolved in 1 L of solution.
- Two types of situation arise giving two kinds of problems:
- Making molar solutions.
Example: Make up a 1.00000 L solution of 0.25 M NaCl
(note that water is the "default" solvent).
First weigh out o.25 moles of NaCl
= (0.25 mole)(22.99 g + 35.45 g)/mole = 14.61 g
Example: What is the concentration of a solution made
by dissolving 10.00 g of KI in enough water to make
1.00000 L?
First need to find the number of moles of KI:
(10.00 g) / ({39.10 g+ 126.9 g}/mole) = 6.135 x 10-2
mole
Thus the concentration will be 6.135 x 10-2
M
- Molality: = moles of solute dissolved in 1 kg of
solvent.
- Mole fraction: = moles of solute dissolved in total
moles of solution = na / S
n
Example: What is the mole fraction of a solution of
10.0 moles of glycerol dissolved in 15.0 moles of water?
(10 mol) / (10 mol + 15 mol) = 10/25 = 0.400
Solubility
- All gases are completely soluble in each other.
- Liquid solutions
- "Like dissolves like."
- Solvation - the process of surrounding a solute with solvent
molecules).
- Hydration (solvation with water).
- Saturation - the maximum amount of solute which can be in
solution in equilibria with its pure state.
- Supersaturation - dissolving solute in excess of saturation
- unstable to the addition of solute (carbonated beverages, honey,
etc.)
- Temperature effects:
- Gases decrease in solubility with increasing temperature.
[example of oxygen solubility]
- Many solids increase in solubility with increasing temperature,
but not always true.
- Pressure effects:
- Gases increase in solubility with increasing pressure (Henry's
Law: P = kC, where k is a constant specific to the solution).
[example of carbonated beverages - p 523 in Zumdahl).
- Note that Henry's Law only holds for gases that are non-reactive
with the solvent - e.g. works for oxygen and nitrogen in water,
does not work for HCl and water (goes to H+ + Cl-)
- Solubility of solids generally uneffected by pressure, since
both liquids and solids essentially incompressible.
Colligative properties
Colligative properties (properties which depend only
on the number or concentration, not on the type, of particles).
[Exchange across surfaces model]
Be able to solve problems for:
- Vapor pressure lowering (Raoult's Law): P = XP°, where
P° = the vapor pressure of the pure substance and X = its
"mole fraction", that is the number of moles of substance
divided by the total number of moles of all substances in the
solution (moles solute/(moles solute + moles solvent)) In other
words the vapor pressure of a substance in solution is proportional
to the molecular percentage of that substance in the solution.
Example: What is the vapor pressure of water in 80 proof alcohol
(XH2O = 0.79) at 25° C (vapor pressure
= 23.76 mmHg).
P = XP°
P = 0.79 (23.76 mmHg) = 18.77 mmHg = 19 mmHg
- Boiling point elevation: DTb
= kbm, where m = molality = moles solute/kg solvent,
and kb is a constant specific to the solvent.
- Freezing point depression: DTf
= -kfm, where m = molality = moles solute/kg solvent,
and kf is a constant specific to the solvent.
- Osmotic pressure (p): pV
= nRT; or, dividing both sides by V, p =
MRT, where M = molarity.
Example: What are the osmotic pressures of 1.00 M sugar and
1 M aluminum chloride solutions at 25°C?
psugar = MRT = (1 mol/L)(0.0821 L*atm/mol*K)(298
K) = 24.5 atm
pAlCl3 = MRT = (1 mol/L)(4 mol ion/mol)(0.0821
L*atm/mol*K)(298 K) = 97.9 atm
Colloids: defined by particle size = 1.0 nm< colloid
< 100 nm (particles in solution are 0.1 - 1.0 nm in diameter,
whereas particles > 100 nm dispersed in a fluid are considered
to be in suspension.) Colloids generally do not settle out.
- Biomacromolecules are often colloidal (proteins, DNA &
RNA)
- particles in inks are sometime colloidal.
Chemical Kinetics
Study of rates and mechanisms of reactions. Experimentally,
look at rates of reactions, use this information to guess mechanisms
- Rate is a measure of how fast the reaction goes. Can measure
how fast a reactant is used up, or how fast a product appears.
Use the stoichiometry of the reaction to relate a particular
rate to the overall reaction rate.
- A mechanism is a detailed description of the steps leading
from reactants to products.
Concentration Dependence of Reaction Rates: Concentrations
are assumed to be in Molarity unless otherwise specified.
Consider the reaction:
A + 2B+ C Æ D + E
- Let's assume that if [A] is doubled while all other concentrations
are unchanged, that the rate doubles. We can then say that the
rate is proportional to [A]; r µ
[A]
- Let's now assume that if [B] is doubled the rate quadruples,
while 3 x [B] gives 9 x rate (again, all other concentrations
are unchanged). We can say that the rate is proportional to the
square of [B]; r µ [B]2.
- Finally let's say that if [C] is changed, no effect is seen
on the rate; r µ [C]0
or r = constant.
- We can now combine these expressions to give
r µ [A] [B]2
[C]0,or
r = k [A] [B]2
This expression is referred to as a Rate Law with
the sum of various exponents referred to as the order of
the reaction. The overall order of this reaction is thus
3rd order - it is first order in A, second order in B, and zero
order in C.
© R A Paselk
Last modified 15 July 2002