| Chem 110 |
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Fall 2003 |
| Lecture Notes::Lec 14_26 September |
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| PREVIOUS |
Last time we finished with a derivation of the Nernst Equation which relates cell potential, E, the standard cell potential, E°, and the mass action potential, Q:
or, substituting values for R, T, and F at 25°C:
We also noted the relationship between free energy and voltage under standard conditions:
So let's use this relationship is a typical problem.
Example: Calculate the voltage for the cell:
Standard potentials for the half reactions are:
Electrons will flow to the more positive half cell, where reduction takes place. Therefore the Ag +/Ag half cell is the cathode, and the Sn2+/Sn half cell must be reversed to become the anode:
Sn(s) Æ Sn2+(aq) + 2e - E°= +0.14 V 2(Ag+(aq) + 2e - Æ Ag(s)) E°= + 0.80 V 2 Ag+(aq) + Sn(s) Æ Ag(s) + Sn2+(aq) E°= + 0.94 V For this reaction the mass action expression, Q, is Q = [Sn2+]/[Ag+]2.
Substituting into the Nernst equation:
E = E° - (RT/nF) ln Q E = 0.94 V - (0.0257/2) ln [0.15]/[0.30]2 E = 0.94 - 0.006564 = 0.947 V = 0.95 V
Concentration cells are cells where the components in the two half cells are identical, but the concentrations differ. So what will the voltage of such a cell be? Consider a cell made up with 0.10 M Ag+ on one side and 1.0 M Ag+ on the other.
Notice that the E° values cancel to give a standard potential of 0.00 V. The question is, which is the anode and which is the cathode?
Let's look at the system qualitatively and see if we can reason which half cell is which.
So the system should be written as:
or, as a cell diagram, with the anode on the left:
We can now use the Nernst equation to calculate the voltage:
E = E° - (RT/nF) ln Q
Note that V is very small (59 mV for a change in concentration of 10). We can use such changes of voltage with concentration as a way of determining concentration called potentiometry.
Potentiometry refers to the use of potential differences to determine concentration differences. The most common and familiar use of potentiometry is in pH meters.
Let's look a bit at how we might determine pH (that is [H+]) by potentiometry.
Calomel (SCE). One of the most common reference electrodes is the so called calomel electrode (named for the calomel filling = Hg2Cl2)
Diagram (note the diagram is for the half cell only):
for the half-reaction:
Note that there is only one variable contributing to the Nernst
equation, the concentration (activity) of chloride ion, since
calomel and mercury are in the pure states and thus have activities
of 1! Thus the potential is:
for the saturated version of the Standard Calomel Electrode (SCE). The SCE is very common because its easy to prepare and very stable, and it has a well defined potential.
The calomel electrode has lost some popularity due to its mercury content. The most common alternate electrode is the Ag/AgCl reference electrode, which we will not discuss.
So now we have a reference electrode, what about the electrode for measuring hydrogen ion? Again the SHE type electrode is difficult to work with and is very rarely used.
The most common electrode for measuring pH is the glass electrode. (overhead - see figure in text)
Let's look at the construction of this electrode (overhead - see figure in text). It can be diagramed, for example, as:
Note the two parts to this electrode: an internal reference electrode (in this case AgCl/Ag, but can also be calomel), and a glass membrane. The two parts are connected by a solution of fixed hydronium activity. Each of these components generates a potential, which generates the overall electrode potential. In making a pH measurement the entire cell, including the reference and indicating electrodes, may be diagramed as:
So how does the electrode work?
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© R A Paselk
Last modified 26 September 2003